Q:

Emily went to a toy store that was selling two Nintendo DS games and four Wii games for a total of $240. Emily bought three DS games and two Wii games and spent $160. What was the price of one Wii game?

Accepted Solution

A:
Answer:The price of one Wii game is $50Step-by-step explanation:Let the cost of 1 Nintendo DS games be xCost of 2 Nintendo DS games = 2xCost of 3 Nintendo DS games = 3xLet the cost of 1 Wii game be y Cost of 4 Wii game = 4yCost of 2 Wii game = 2yNow we are given that Emily went to a toy store that was selling two Nintendo DS games and four Wii games for a total of $240So, [tex]2x+4y = 240[/tex] Β --- AEmily bought three DS games and two Wii games and spent $160So, [tex]3x+2y = 160[/tex] ---- BPlot lines A and B on graph . Intersection point will provide the solution .[tex]2x+4y = 240[/tex] Β  -- Green[tex]3x+2y = 160[/tex] -- BlueIntersection Point = (20,50)So, Cost of 1 Nintendo DS games = $20Cost of 1 Wii game = $50Hence the price of one Wii game is $50