The bottom of the meniscus of your solution falls between the second and third marking from the 12 mL mark of the nine markings between the 12 mL and 13 mL mark on your buret. The bottom of the meniscus is a little closer to the second mark than the third. How would you report this volume? 12 mL

Answer:V = 12.2 mL Step-by-step explanation:      First, we need to find the smallest division in the scale of the buret, considering the nine markings between 12 mL and 13 mL on the buret:   [tex]n= \frac{(13 - 12)}{9} = 0.111 mL[/tex]     Between the second and the third marking from the 12 mL mark, the volume is:     [tex]V= n*2 + \frac{n}{2} = 0.11*2 + \frac{0.11}{2} = 0.275 mL [/tex]    So, we can now calculate the volume in the buret:[tex]V= 0.275 + 12 = 12.2 mL [/tex]     Have a nice day!