At a busy street corner, one of every hundred jaywalkers will be hit when they cross. What is the probability of a jaywalker not being hit if he makes a round trip daily for thirty days? (0.01)30 (0.99)30 (0.9801)30

Answer: Last option[tex]p = (0.9801) ^ {30}[/tex]Step-by-step explanation:the probability of a jaywalker being hit is [tex]P = \frac{1}{100} = 0.01[/tex]. So the probability of a jaywalker not being hit is: [tex]P '= 1-0.01[/tex][tex]P '= 0.99[/tex]As in this experiment the probability of each trial is independent then, the probability that it is not a jaywalker will not be hit if it makes a round trip is: [tex]P '= (0.99) (0.99) = 0.9801[/tex][tex]P '= 0.9801[/tex]If this experiment is repeated for 30 days then the probability that it is not a jaywalker will not be hit if it makes a round trip is: [tex]p = (0.9801) ^ {30}[/tex]